n^2+2.5n-6=0

Solution for n^2+2.5n-6=0 equation:

n^2+2.5n-6=0

a = 1; b = 2.5; c = -6;
Δ = b2-4ac
Δ = 2.52-4·1·(-6)
Δ = 30.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.5)-\sqrt{30.25}}{2*1}=\frac{-2.5-\sqrt{30.25}}{2}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.5)+\sqrt{30.25}}{2*1}=\frac{-2.5+\sqrt{30.25}}{2}
$